2(2t^2+3t+5)-4(t^2+2t-1)=6

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Solution for 2(2t^2+3t+5)-4(t^2+2t-1)=6 equation:


Simplifying
2(2t2 + 3t + 5) + -4(t2 + 2t + -1) = 6

Reorder the terms:
2(5 + 3t + 2t2) + -4(t2 + 2t + -1) = 6
(5 * 2 + 3t * 2 + 2t2 * 2) + -4(t2 + 2t + -1) = 6
(10 + 6t + 4t2) + -4(t2 + 2t + -1) = 6

Reorder the terms:
10 + 6t + 4t2 + -4(-1 + 2t + t2) = 6
10 + 6t + 4t2 + (-1 * -4 + 2t * -4 + t2 * -4) = 6
10 + 6t + 4t2 + (4 + -8t + -4t2) = 6

Reorder the terms:
10 + 4 + 6t + -8t + 4t2 + -4t2 = 6

Combine like terms: 10 + 4 = 14
14 + 6t + -8t + 4t2 + -4t2 = 6

Combine like terms: 6t + -8t = -2t
14 + -2t + 4t2 + -4t2 = 6

Combine like terms: 4t2 + -4t2 = 0
14 + -2t + 0 = 6
14 + -2t = 6

Solving
14 + -2t = 6

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + -2t = 6 + -14

Combine like terms: 14 + -14 = 0
0 + -2t = 6 + -14
-2t = 6 + -14

Combine like terms: 6 + -14 = -8
-2t = -8

Divide each side by '-2'.
t = 4

Simplifying
t = 4

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